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A wire of length 1.6m has a resistance `8 Omega` is connected to a battery of 2 volts and internal resistance `2Omega`. What is the potential gradient ?A. `1.5V//m`B. `0.5V//m`C. `1V//m`D. `2V//m` |
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Answer» Correct Answer - C `l=1.6 m, R=8Omega, E=2V, r=2 Omega, I rho=?` `I rho =((E)/(R+r))(R)/(l)` `=((2)/(8+2))(8)/(1.6)=(16)/(16)=1 V//m` |
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