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| 1. |
A wire of given material having length ' L ' and area of cross - section ' A ' has a resistance of 6 ohm . What should be the resistance of another wire of same material having length 1/3 and are of cross section 3 A ? |
| Answer» 1 ohmExplanation:Resistance = P l/a [ p is constant]For first wire length = l and area of croos section = aResistance = p l/a = 4 ohm [GIVEN]For SECOND wire length = l/2 and area of cross section = 2aResistance = p (l/2) / 2a = p l/4a = p l/a * 1/4 [p l/a = 4 ohm] = 4*1/4 = 1 ohmThe resistance of second wire = 1 ohm | |