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A wire of given material having length ' L ' and area of cross - section ' A ' has a resistance of 6 ohm . What should be the resistance of another wire of same material having length 1/3 and are of cross section 3 A ?

Answer» 1 ohmExplanation:Resistance = P l/a [ p is constant]For first wire length = l and area of croos section = aResistance = p l/a = 4 ohm [GIVEN]For SECOND wire length = l/2 and area of cross section = 2aResistance = p (l/2) / 2a                   = p l/4a                   = p l/a * 1/4 [p l/a = 4 ohm]                   = 4*1/4 =  1 ohmThe resistance of second wire = 1 ohm


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