A wire is in the shape of a rectangle. Its length is 40 cm and breadth

1.	A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is bent in the shape of a square, what will be the measure of each side. Also, find which side encloses more area?
Answer» Given length of rectangular shaped wire = 40 cm Breadth of rectangular shaped wire = 22 cm Perimeter of the rectangle = 2(Length + Breadth) = 2(40 cm + 22 cm) = 124 cm It is given that the wire which was in the shape of a rectangle is now bent into a square. Therefore, the perimeter of the square = Perimeter of the rectangle Perimeter of the square = 124 cm We know that perimeter of square = 4 x side Therefore 4 x side = 124 cm Side = 124/4 = 31 cm We know that area of rectangle = length x breadth Now, Area of the rectangle = 40 cm x 22 cm = 880 cm² We know that area of the square = (Side)² = (31 cm)² = 961 cm². Therefore, the square-shaped wire encloses more area.

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is bent in the shape of a square, what will be the measure of each side. Also, find which side encloses more area?

Answer»

Given length of rectangular shaped wire = 40 cm

Breadth of rectangular shaped wire = 22 cm

Perimeter of the rectangle = 2(Length + Breadth)

= 2(40 cm + 22 cm)

= 124 cm

It is given that the wire which was in the shape of a rectangle is now bent into a square.

Therefore, the perimeter of the square = Perimeter of the rectangle

Perimeter of the square = 124 cm

We know that perimeter of square = 4 x side

Therefore 4 x side = 124 cm

Side = 124/4 = 31 cm

We know that area of rectangle = length x breadth

Now, Area of the rectangle

= 40 cm x 22 cm

= 880 cm²

We know that area of the square = (Side)²

= (31 cm)²

= 961 cm².

Therefore, the square-shaped wire encloses more area.