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A wire is bent so as to form four sides of a square. A length of 4 cm is cut from it and the remainder is again bent to form the four sides of a square. If the difference in areas of square is 25 cm^2, how long was the wire before being cut? |
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Answer» Answer: Let X as side of the SQUARE so area of the square is x^2,total LENGTH of the wire is 4x Now 4cms is cut from 4x,remaining length is 4x-4=4(x-1)CMS length of the side is x-1)cms Original area of square is x^2 After removing 4cms area of the square formed (x-1)^2=x^2–2x+1 Given the DIFFERENCE in areas of the square is 25cm2 So x^2-x^2+2x-1=25 2x-1=25 x=(25+1)/2=13 So the length of the wire was 4*13=52cms hope it helps........................ |
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