1.

a wire has resistanse 90ohm. it is bent in the form of equilateral triangle .the effective resistanse between the corners is?

Answer» R in UPPER arm=2x90/3=60
r in LOWER arm=30
effective r=
\frac{1}{60}  +  \frac{1}{30}  = <klux>20</klux>
ans is 20 ohms

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