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A wire has resistance of `10Omega`. If it is stretched by 1/10th of its length, then its resistance is nearlyA. `9Omega`B. `10Omega`C. `11Omega`D. `12Omega` |
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Answer» Correct Answer - D Resistance of wire `R = rho l//A =10 Omega,` New length, `l_(1)=l+l//10=11//10` `therefore` New are, `A_(1)=Al // l_(1)=(10A)/(11)` `therefore` New resistance, `R_(1)=rho l_(1)//A_(1)=rho(11//10)//(10//11)A` `= (121 rho l)/(100 A)=(121)/(100)xx10` `= 12.1 Omega` |
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