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A wire 1m long has a resistance of `1 Omega`. If it is uniformly stretched, so that its length increases by 25% then its resistance will increase byA. 0.25B. 0.5C. 0.5625D. 0.7733 |
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Answer» Correct Answer - C `R_(2)=n^(2)R_(1)=(1.25)^(2)R_(1)=1.5625xx1` `=1.5625 Omega` Thus, increase in resistance is , `R_(2)-R_(1)=1.5625-1=0.5625Omega=56.25 %` |
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