1.

A whistle giving out a sound of frequency 450Hz , approaches a stationary observer at a speed of 33ms_(1). The frequency heard by the observer is (speed of sound =330m s_(1)____.

Answer»


Solution :APPARENT frequency `n.=((v)/(v-v_(s)))n`
`=((330)/(330-33))xx450=1.11xx450`
n.=500Hz
Data: `v=330ms^(-1)`
`v_(s)=33ms^(-1)`
n=450Hz
n.=?


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