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A wheel is making 600 rpm. Find the time taken by it to come to rest with retardation rad/sec2 |
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Answer» ong>ANSWER: Correct OPTION is A π/2 Initially ν=900r.p.m= 60 900
=15 s −1
Thus ω 1
=2πν=30π rad/s and ω 2
=0 Using, ω 2
=ω 1
+αt, where t=60 s, we get: 0=30π+α(60) or, α=− 2 π
rad/s 2 (-ve SIGN shows angular retarding acceleration) |
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