A wheel having moment of inertia 2kgm^(2) about its vertical axis, rotates at the rate of 60 rpm about the axis. The torque which can stop the wheel.s rotation in one minute would be……………

A wheel having moment of inertia 2kgm^(2) about its vertical axis, rot

1.	A wheel having moment of inertia 2kgm^(2) about its vertical axis, rotates at the rate of 60 rpm about the axis. The torque which can stop the wheel.s rotation in one minute would be……………
Answer» `(pi)/(18)N/m` `(2pi)/(15)N.m` `(pi)/(12)N.m` `(pi)/(15)N.m` Solution :`Deltat=60sec` SPEED of wheel = 60 RPM `therefore v=("60 revolution")/("minute")` `=(60xx2pir)/(60 sec)` `v=2pir` but `omega=(v)/(r )` `omega=2pi` For stopping wheel, (Necessary moment of torque) = (angular momentum of wheel) `therefore TAU.Deltat=Iomega` `therefore tau(60)=(2 kg m^(2))(2pi)` `therefore tau=(4pi)/(60)N.m` `=(pi)/(15)N.m`