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A wheel having moment of inertia 2 kg m^(2) about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel's rotation in one minute would be |
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Answer» `(2pi)/15Nm` `thereforealpha=omega_(i)//t,` where `ALPHA` is RETARDATION. The torque on the wheel is GIVEN by `tau=Ialpha=(Iomega_(i))/t=(I.2piv)/t=(2xx2xxpixx60)/(60xx60)` `rArr=pi/15` Nm This is the torque REQUIRED to stop the wheel in 1 min. (or 60 sec.). |
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