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(a) What is the power of an engine which can lift 600 kg of coal per minut from a mine 20 m deep ? (b) A 2kW motor pumps out water from a well `10m` deep. Calculated the quantity of water pumped out per second. |
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Answer» `overlineP=(W)/(t)=(mgh)/(t)=(600xx10xx20)/(60)=2000W` (b) `overlineP=(W)/(t)=(mgh)/(t)` `2000=(m)/(t)xx10xx10` `(m)/(t)=20` Quantity of water pumped out per second `=20kg` |
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