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A water fountain on the ground sprinkles water all around it. If the speed of the water coming out of the fountain is v. Calculate the total area around the fountain that gets wet. |
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Answer» `:.` Rang of the particle `(R_(max))=(V^(2))/(g)sin2theta=(v^(2))/(g)` here, `R_(max)` is radius of the area covered. `:.` area covered `pir^(2)=piR_(max)^(2)=PI((v^(2))/(g))" Area" (piv^(2))/(g^2)` |
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