1.

A water fountain on the ground sprinkles water all around it. If the speed of the water coming out of the fountain is v. Calculate the total area around the fountain that gets wet.

Answer»


Solution :Water comes from a fountain can be TAKEN as projectile and the distance covered is MAXIMUM range of projectile i.e., `theta=45^(@)`
`:.` Rang of the particle `(R_(max))=(V^(2))/(g)sin2theta=(v^(2))/(g)`
here, `R_(max)` is radius of the area covered.
`:.` area covered `pir^(2)=piR_(max)^(2)=PI((v^(2))/(g))" Area" (piv^(2))/(g^2)`


Discussion

No Comment Found