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A water drop of radius `10^-2` m is brokenn into 1000 equal droplets. Calculate the gain in surface energy. Surface tension of water ils `0.075Nm^-1`A. `16.96xx10^(-4) J`B. `8.48 xx 10^(-4) J`C. `4.24 xx 10^(-4) J`D. `2.12 xx 10^(-4) J` |
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Answer» Correct Answer - B Gain in surface energy `E=4piR^(2)(n^(1/3)-1)T` `=4 xx 3.14 xx (10^(-2))(1000)^(1//3)-1 xx 0.075` `=8.48 xx 10^(-4)` J |
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