1.

A voltmeter has a resistance of `50 Omega` is connected across a cell of e.m.f. 2V and internal resistance `10 Omega`. The reading of voltmeter isA. 1.667VB. 16.7VC. 167VD. 0.167V

Answer» Correct Answer - A
`V=I R=((E)/(R+r))R=((2)/(50+10))50=1.667 V`


Discussion

No Comment Found

Related InterviewSolutions