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A vessel with water is placed on a weighing pan and reads `600g`. Now a ball of 40g and density `0.80g//c c` is sunk into the water with a pin as shown in fig. keeping it sunk. The weighing pan will show a reading A. 600gB. 550gC. 650gD. 632g |
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Answer» Correct Answer - C Upthrust on ball = weight of displaced water `= V sigma g = ((m)/(rho)) sigma g = (40)/(0.8) xx 1xx g = 50g` As the ball is sunk into the water with a pin by applying downward force equal to upthrust on it. So reading of weighing pan `=weight of water + downward force against upthrust =600+50 = 650 gm`. |
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