A vessel of 250 litre was filled with 0.01 mole of Sb2S3 and 0.01 mole of H2 to attain the equilibrium at 440 °C as Sb2S3(s)+3H2(g)⇌2Sb(s)+3H2S(g). After equilibrium, the H2S formed was analysed by dissolving it in water and treating with excess of Pb2+ to give 1.195 g of PbS as precipitate. What is the value of KC at 440 °C? (Molar mass of Pb= 207 gmol−1)

A vessel of 250 litre was filled with 0.01 mole of Sb2S3 and 0.01 mol

1.	A vessel of 250 litre was filled with 0.01 mole of Sb2S3 and 0.01 mole of H2 to attain the equilibrium at 440 °C as Sb2S3(s)+3H2(g)⇌2Sb(s)+3H2S(g). After equilibrium, the H2S formed was analysed by dissolving it in water and treating with excess of Pb2+ to give 1.195 g of PbS as precipitate. What is the value of KC at 440 °C? (Molar mass of Pb= 207 gmol−1)
Answer» A vessel of 250 litre was filled with 0.01 mole of $S b_{2} S_{3}$ and 0.01 mole of $H_{2}$ to attain the equilibrium at $440 ° C$ as $S b_{2} S_{3} (s) + 3 H_{2} (g) ⇌ 2 S b (s) + 3 H_{2} S (g)$ . After equilibrium, the $H_{2} S$ formed was analysed by dissolving it in water and treating with excess of $P b^{2 +}$ to give $1.195 g$ of $P b S$ as precipitate. What is the value of $K_{C}$ at $440 ° C$ ? (Molar mass of $P b = 207 g m o l^{- 1}$ )