1.

A vessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35°C. What would be its pressure?

Answer»

Here, temperature remains constant. Then for a certain amount of gas

p1V1 = p2V2

1.2 bar x 120 mL = P2 x 180 mL

or, p2 = {1.2 bar x 120 mL}/{180 mL}

= 0.8 bar



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