1.

A vessel contains oil of density 0.8gm//cm^(3) over mercury of density 13.6gm//cm^(3) .Solid sphere floats with half of its volume immersed in mercury and the other half in the oil . The density of the sphere is ….. gm//cm^(3).

Answer»

`3.3`
`6.4`
`7.2`
`12.8`

Solution :
LET density of sphere is `rho` ,
Density of oil is `rho_(1)` and density of mercury is `rho_(2)` Weight of sphere `W=(4)/(3)PIR^(3)rhog`….(1)
Where R= RADIUS of sphere
BUOYANT force on sphere in oil ,
`F_(1)=(2)/(3)piR^(3)rho_(1)g`....(2)
Buoyant force on sphere in mercury,
`F_(2)=(2)/(3)piR^(2)rho_(2)g`....(3)
Weight of sphere `W=F_(1)+F_(2)`
`therefore(4)/(3)piR^(3)rhog=(2)/(3)piR^(3)rho_(1)g+(2)/(3)piR^(3)rho_(2)g`
`therefore2rho=rho_(1)+rho_(2)`
`therefore2rho=0.8+13.6`
`therefore2rho=14.4`
`thereforerho=7.2gcm^(-3)`


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