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A vessel contains 100 liters mixture ofmilk and water in the respective ratio of22 : 3. 40 liters of the mixture is takenout from the vessel and 4.8 litters ofpure milk and pure water each is addedto the mixture. By what percent is thequantity of water in the final mixture lessthan the quantity of milk? |
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Answer» Answer: MARK AS BRAINLIEST AND FOLLOW ME Step-by-step EXPLANATION: REMAINING mixture in the vessel = 60 litres Milk = 2225×60 = 52.8 litres Water = 7.2 litres On adding additional milk and water. Milk = 52.8 + 4.8 = 57.6 litres Water = 7.2 + 4.8 = 12 litres Therefore, REQUIRED PERCENT = 57.6−1257.6×100 =45.657.6×100 =4756=7916 |
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