1.

A vessel containing air of mass 8g at 400 K is provided with a hole so that some amount of air leaks out. After some time, the pressure is halved and temperature is changed to 300 K. The mass of air escaped is:

Answer»

4g
2.7 g
5.3 g
2g

Solution :We know `(P)/(rho T)`= constant. But `rho prop m`
`therefore (P)/(mT)` = constant.
Now `(P)/(8xx400)=(P)/(2) xx (1)/(m.) xx (1)/(300)`
or `m.=(3200)/(600) =(16)/(3)=5.3 g`
MASS escaped `=8-5.3 =2.7 g`
`therefore` CORRECT choice is (b).


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