1.

A very broad elevator is going up vertically with the constant acceleration 1 m per second square at the instant when the velocity of the lift is 2m per second a stone is projected from a floor of the left his feet to metre per second related floor at an elevation 30 degree find

Answer»

t of VELOCITY of ball relative to lift areux=4cos30∘=23–√m/sux=4cos⁡30∘=23m/suy=4sin30∘=2m/suy=4sin⁡30∘=2m/sand acceleration of ball relative to lift is a=10+2=12m/s2a=10+2=12m/s2 in NEGATIVE y DIRECTION ACTING downwards.Therefore Time of flight T=2uyaT=2uya=2×212=2×212=13s=13sHence b is the correct answer.



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