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.. A vertical wire in which a current is flowingproduces a neutral point with the earth's magneticfield at a distance of 10 cm from the wire. What isthe current if Bh = 1.8 x 10-4 T? (Ans. 90 A)​

Answer»

Magnetic Field due to a current CARRYING wire is

B = (ui/2πr)

Since, it neutralizes the Earth's magnetic field. Thus, B = Bh

ui/2πr = 1.8 × 10^-4

i = (1.8×2π×0.1/u) × 10^-4

i = 0.09 × 10^7 × 10^-4 AMPERE

i = 0.09 × 10^3 Ampere

i = 90 Ampere



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