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A vertical pole of length 3 m casts a shadow of 7 m and a tower casts a shadow of 28 m at a time. Find the height of tower. class 10 |
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Answer» ong>Step-by-step explanation: ANSWER Height of pole=AB=6 m Length of shadow of pole =BC=4 m Length of shadow of TOWER=EF=28 m In △ABC and △DEF ∠B=∠E=90 ∘ both 90 ∘ as both are vertical to ground ∠C=∠F (same elevation in both the cases as both shadows are cast at the same time) ∴△ABC∼△DEF by AA similarity criterion We KNOW that if two triangles are similar, RATIO of their sides are in proportion So, DE AB
= EF BC
⇒ DE 6
= 28 4
⇒DE=6×7=42 m Hence the height of the tower is 42 m please add to brainlist please follow me and thanks I will follow u |
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