A vertical pole 20 m long cast a shadow 20√3 m long. Find the sun’

1.	A vertical pole 20 m long cast a shadow 20√3 m long. Find the sun’saltitude. At the same time, a tower casts a shadow 90 m long ,determine the height of the tower
Answer» In ΔABC & ΔADE ∠BCA=∠DEA=90O [Each are at 90o to the ground] ∠BAC=∠DAE [common angle] ∠CBA=∠EDA [∵ the sum will cast LIGHT a equal angles] HENCE, by AAA, ΔABC∼ΔADE ⇒CABC=EADE ⇒1020=50DE ⇒DE=100 ∴ The height of the tower is 100m.

A vertical pole 20 m long cast a shadow 20√3 m long. Find the sun’saltitude. At the same time, a tower casts a shadow 90 m long ,determine the height of the tower

Answer»

In ΔABC & ΔADE

∠BCA=∠DEA=90O [Each are at 90o to the ground]

∠BAC=∠DAE [common angle]

∠CBA=∠EDA [∵ the sum will cast LIGHT a equal angles]

HENCE, by AAA, ΔABC∼ΔADE

⇒CABC=EADE

⇒1020=50DE

⇒DE=100

∴ The height of the tower is 100m.

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A vertical pole 20 m long cast a shadow 20√3 m long. Find the sun’saltitude. At the same time, a tower casts a shadow 90 m long ,determine the height of the tower

In ΔABC & ΔADE

∠BCA=∠DEA=90O [Each are at 90o to the ground]

∠BAC=∠DAE [common angle]

∠CBA=∠EDA [∵ the sum will cast LIGHT a equal angles]

HENCE, by AAA, ΔABC∼ΔADE

⇒CABC=EADE

⇒1020=50DE

⇒DE=100

∴ The height of the tower is 100m.

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