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A vernier caliper with a least count of of `0.01 cm` was used to measure diameter of cylinder as `4 cm` and a scale `(0-15cm)` with the least count of `1 mm` was used to measue a length of `5cm`. The `%` error in the measurement of volume of the cylinder isA. `3.0`B. `4.0`C. `5.0`D. `2.5` |
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Answer» Correct Answer - D `V=(pid^2)/4l` `implies(/_V)/V=(2/_d)/d+(/_l)/l=(2xx0.01)/4+0.1/5=1/40` % error is volume `=(/_V)/Vxx100=2.5%` |
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