A vehicle is moving with a velocity of 9.8 m/s, whose mass is 200 kg.

1.	A vehicle is moving with a velocity of 9.8 m/s, whose mass is 200 kg. What is the magnitude of force required to stop the vehicle in 10 sec?
Answer» Answer: Given MASS of the vehicle(m)=120 kg and initial VELOCITY u= 90 km/h u=90km/h=90×( 18 5 )=25 m/s As the vehicle is needed to be stopped in 10 SECONDS the final velocity will be =0 m/s. We know acceleration= time Final−initialvelocity = 10 0−25 =−2.5m/s 2 And also Force= mass×acceleration =120×(−2.5)=−300N {The negative sign implies that the force is applied in the direction opposite to that of the direction of motion} EXPLANATION:

A vehicle is moving with a velocity of 9.8 m/s, whose mass is 200 kg. What is the magnitude of force required to stop the vehicle in 10 sec?

Answer»

Answer:

Given MASS of the vehicle(m)=120 kg and initial VELOCITY u= 90 km/h

u=90km/h=90×(

)=25 m/s

As the vehicle is needed to be stopped in 10 SECONDS the final velocity will be =0 m/s.

We know acceleration=

time

Final−initialvelocity

0−25

=−2.5m/s

And also Force= mass×acceleration

=120×(−2.5)=−300N

{The negative sign implies that the force is applied in the direction opposite to that of the direction of motion}