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| 1. |
A vector =2i-j+k,B vector=i-j find theta? |
| Answer» LET a=i^+j^+k^ and b=2i^−2j^+2k^ and ANGLE between them be θThen, cosθ=∣a∣∣b∣a⋅b=(1)2+(1)2+(1)2(2)2+(−2)2+(2)2(i^+j^+k^)⋅(2i^−2j^+2k^)=3122−2+2=62=31⇒θ=cos−1(31) | |