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A variable current flows through a `1Omega` resistor for 2 s. Time dependence of the current is shown in the graph. A. Total charge flowing through the resistor is 10C.B. Average current through the resistor is 5 A.C. Total heat produced in the resistor is 50J.D. Maximum power during the flow of current is 100 W. |
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Answer» Correct Answer - A::B::D a., b., d. "Total charge" `= int I dt ` = "Area under the curve" = `10 C`. "Average current" `= (int I dt)/(int dt) = 5A` "Total heat produced" `= (int I^2 dt)` `= int_(0)^(2) (-5t + 10)^2 1dt = 200/3J` "Maximum power" = `I^2R` "when I is maximum current" `= 100 xx 1 = 100W`. |
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