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A uniformly charged spherical shell of radius R and charge Q is rotating about its diameter with constant angular speed ω. The magnetic moment of shell is |
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Answer» The magnetic moment \(\frac ML=\frac{q}{2m}\) M = \(\frac{q}{2m}L\) \(\because\) L = I\(\omega\) Moment of inertia of spherical shell about diameter I = \(\frac23mR^2\) Then M = \(\frac{q}{2m}I\omega\) = \(\frac{q}{2m}(\frac23MR^2\omega)\) = \(\frac{qm\omega R^2}{3m}\) M = \(\frac{q\omega R^2}3\) |
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