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A uniform wire resistance `20 Omega` having resistance `1 Omega per meter, ` is bent in the forms of a circuit if the equal - valent resistance between A and B is `1.8 Omega ` then length of the shorter section is A. 2mB. 5mC. 1.8 mD. 18m |
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Answer» Correct Answer - A Let the resistance of shorter part MN be x. Then resistance of longer part is `(20-x)Omega` `R_(eq)=((20-x)x)/(20-x+x)=1.8Omega` solving we get `x=2Omega` So length of shorter part `=2m` |
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