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A uniform string of length 10 m is suspended from a rigid support A short wave pulse is introduced at its lowest end it starts moving up the string the time taken to reach the support is (take `g=10m//sec^(2)`)A. 1 secB. 2 secC. `2sqrt(2)`D. 4 sec |
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Answer» Correct Answer - B Let mass per unit length be `mu`. Tension at a distance `x` from lowest point is `T=mugx` `V=sqrt((T)/(mu))=sqrt(gx)` `v^(2)=gx` `a=(vdv)/(dx)=(g)/(2)` `l=(1)/(2)((g)/(2))t^(2)` `t=sqrt((4l)/(g))=sqrt((4xx10)/(10))=2sec`. |
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