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A uniform string of length 10 m is suspended from a rigid support A short wave pulse is introduced at its lowest end it starts moving up the string the time taken to reach the support is (take `g=10m//sec^(2)`) |
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Answer» Correct Answer - 2 Let mass per unit length be `mu`. Tension at a distance `x` from lowest point is `T=mugx` `v=sqrt((T)/(mu))=sqrt(gx),v^(2)=gx` `a=(vdv)/(dx)=(g)/(2),l=(1)/(2)((g)/(2))t^(2)` `t=sqrt((4l)/(g))=sqrt((4xx10)/(10))=2sec` |
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