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A uniform rope of length 12m and mass 12kg hangs vertically from a rigid support. A block of mass 2kg is attached to free end of the rope. A traverse pulse of wave length 0.05 m is produced at the lower end of the rope. If `lambda` is the wave length when pulse reached at mid point of the rope, then write `10lambda` in the OMR sheet. |
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Answer» `v=fllambda` `(lambda_(1))/(lambda_(2))=(v_(1))/(v_(2_sqrt(T_(1))/sqrt(T_(2))` `(0.05)/(lambda_(2))=sqrt((2xxg)/((2+6)g))=sqrt((1)/(4)=(1)/(2)` `lambda_(2)=0.1` |
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