1.

A uniform rod of mass m, hinged at its upper end, is released from rest from a horizontal position. When it passes through the vertical position, the force on the hinge is (a) 3/2 mg (b) 2mg (c) 5/2 mg (d) 3mg

Answer»

Correct Answer is: (c) 5/2 mg

mg. l/2 = 1/2 Iω2 = 1/2. ml2/3 ω2.

or ω2 = 3g/l.

Now, N - mg = mω2 l/2 = m. 3g/l . l/2 = 3/2 mg

or N = 5/2 mg.



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