A uniform rod AB of mass 'm' length 2a is allowed to fall under gravity with AB in horizontal. When the speed of the rod is 'v', suddenly the end 'A' is fixed. Find the angular velocity with which it begins to rotate .

A uniform rod AB of mass 'm' length 2a is allowed to fall under gravit

1.	A uniform rod AB of mass 'm' length 2a is allowed to fall under gravity with AB in horizontal. When the speed of the rod is 'v', suddenly the end 'A' is fixed. Find the angular velocity with which it begins to rotate .
Answer» Solution :`L_(1)=L_(2)` `mva=Iomega` `mva=(m(2a)^(2))/(3)omegaimpliesomega=(3V)/(4A)`