1.

A uniform ring is rotating about vertical axis with angular velocity omega initally. A point insect (S) having the same mass as that of the ring starts walking from the lowest point P_(1) and finally reaches the point P_(2) (as shown in figure). What is the final angular velocity of the ring ? .

Answer»


Solution :from conservation of angular MOMENTUM
`((1)/(2) MR^(2)) OMEGA = ((1)/(2) MR^(2) + MR^(2)) omega'`
`((1)/(2) MR^(2)) omega = ((3)/(2) MR^(2)) omega' rArr omega' = (omega)/(3)`.


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