A uniform meter rod of 2 N is pivoted at 60 cm mark.The total length o

1.	A uniform meter rod of 2 N is pivoted at 60 cm mark.The total length of meter rod is 100 cm.If a load of 4 N is suspended at one end 40 cm from pivot point.What is the net torque about the pivot.
Answer» Torque DUE to LOAD =4N×40cm=1.6Nm Torque due to WEIGHT of the RULE =2N×10cm=0.2Nm Both are in opposite to each other so NET torque =1.6−0.2=1.4Nm

A uniform meter rod of 2 N is pivoted at 60 cm mark.The total length of meter rod is 100 cm.If a load of 4 N is suspended at one end 40 cm from pivot point.What is the net torque about the pivot.

Answer»

Torque DUE to LOAD =4N×40cm=1.6Nm

Torque due to WEIGHT of the RULE =2N×10cm=0.2Nm

Both are in opposite to each other so NET torque =1.6−0.2=1.4Nm

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A uniform meter rod of 2 N is pivoted at 60 cm mark.The total length of meter rod is 100 cm.If a load of 4 N is suspended at one end 40 cm from pivot point.What is the net torque about the pivot.

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