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A uniform magnetic field is restricted within a region of radius r. The magnetic field changes with time at a rate `(dB)/(dt)`. Loop 1 of radius R `gt` r encloses the region r and loop 2 of radius R is outside the region of magnetic field as shown in figure. Then, the emf generated is A. Zero in loop 1 and zero in loop 2B. `-(dB)/(dt)pir^(2)` in loop 1 and `-(dB)/(dt)pi^(2)` in loop 2C. `-(dB)/(dt)piR^(2)` in loop 1 and zero in loop 2D. `-(dB)/(dt)pir^(2)` in loop 1 and zero in loop 2 |
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Answer» Correct Answer - C Induced emf in the region is given by `|e|=(dhpi)/(dt)` where, `phi=BA=pir^(2)B` `rArr" "(dphi_(1))/(dt)-pir^(2)(dB)/(dt)` Rate of change if magnetic flux associated with loop l, `e_(1)=-(dphi_(1))/(dt)=-pir^(2)(dB)/(dt)` Similarly, `e_(2)` = emf associated with loop 2 `=-(dphi_(2))/(dt)=0" "(because phi_(2)=0)` |
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