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A uniform magnetic field `B` exists in a cylindrical region of radius `I0cm` as shown in figure. A uniform wire or length `80cm` and resistance `44.0Omega` is bent into a square frame and is placed with one side along a diameter of the cylindrical region. if the magnetic field increases at a constant rate of `0.0I0T//sec` , the current induced in the frameA. `3.9xx10^(-5)A`B. `4.0xx10^(5)A`C. `4.1xx10^(-5)A`D. `3.9xx10^(-4)A` |
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Answer» Correct Answer - A Only half area of ring area of ring will be considered. `therefore phi_(B)=BS=B.(pir^(2))/(2)` `thereforee=(dphi_(B))/(dt)=(pir^(2))/(2).(dB)/(dt)=(pi(0.1)^(2))/(2)xx0.01=(pi)/(2)xx10^(-4)V` `thereforei=(e)/(R)=((pi)/(2)xx10^(-4))/(4)=(pi)/(8)xx10^(-4)=3.9xx10^(-5)A` |
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