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A uniform long tube is bent into a circle of radius R and it lies in vertical plane. Two liquids of same volume but densities `rho " and " delta` fill half the tube. The angle `theta` is A. `tan^(-1) ((rho-delta)/(rho+delta))`B. `tan^(-1)((rho)/(delta))`C. `tan^(-1)((delta)/(rho))`D. `tan^(-1)((rho+delta)/(rho-delta))` |
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Answer» Correct Answer - A From the figure, we have `delta gR(cos theta+sin theta)=rho gR(cos theta - sin theta)` `implies delta cos theta+ delta sin theta= rho cos theta- rho sin theta` `implies sin theta(delta+rho)=cos theta(rho-delta) implies tan theta=(rho-delta)/(rho+delta)` |
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