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A uniform electric field of 400 V/m is directed at 45 degree angle from positive x-axis as shown in figure. the potential difference Va-vb is given by |
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Answer» Answer: Explanation: => E = Ex(i)+Ey(j) E=Ecos45⁰(i)+Esin45⁰(j) =E/√2(i) + E/√2(j) = E/√2(i+j)
= = 400/√2 * 0.01 = 400 * 0.01/1.414 =2.83 V Thus, the potential difference Va-vb is GIVEN by 2.83 V |
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