A uniform electric field E = 8000 N/C is passing through a flat square

1.	A uniform electric field E = 8000 N/C is passing through a flat square area A = 10 m2making an angle of 60 ֠ . Determine the electric flux
Answer» Given INFO : A UNIFORM electric field E = 8000 N/C is passing through a flat square area A = 10 m² MAKING an angle of 60° . To find : The electric FLUX in this uniform field is ... SOLUTION : angle made by electric field with flat surface is 60°. as we know, area vector is normal to the surface of it. so, angle between electric field and area vector is (90° - 60°) = 30° now electric flux = EAcosΦ = 8000 N/C × 10 m² × cos30° = 80000 × √3/2 = 40000√3 Nm²/C = 69282 Nm²/C Therefore the electric flux is 69282 Nm²/C.

A uniform electric field E = 8000 N/C is passing through a flat square area A = 10 m2making an angle of 60 ֠ . Determine the electric flux

Answer»

Given INFO : A UNIFORM electric field E = 8000 N/C is passing through a flat square area A = 10 m²

MAKING an angle of 60° .

To find : The electric FLUX in this uniform field is ...

SOLUTION : angle made by electric field with flat surface is 60°. as we know, area vector is normal to the surface of it. so, angle between electric field and area vector is (90° - 60°) = 30°

now electric flux = EAcosΦ

= 8000 N/C × 10 m² × cos30°

= 80000 × √3/2

= 40000√3 Nm²/C

= 69282 Nm²/C

Therefore the electric flux is 69282 Nm²/C.

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