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A uniform disk of mass `300kg` is rotating freely about a vertical axis through its centre with constant angular velocity `omega .` A boy of mass `30kg` starts from the centre and moves along a radius to the edge of the disk. The angular velocity of the disk now isA. `(omega_(0))/(6)`B. `(omega_(0))/(5)`C. `(4omega_(0))/(5)`D. `(5 omega_(0))/(6)` |
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Answer» Correct Answer - D As `Sigma tau =0` , angular momentum remains conserved `:` `:. L=(0+(300R^(2))/(2))` `omega_(0)=((300R^(2))/(2)+30R^(2)).omega` `=150 omega _(0)=180 omega` `rArr omega = 5/6 omega _(0) Ans. ` |
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