A uniform disc of radius R (3 m) has a round disc of radius R/3 cut from it as shown in the figure. The mass of the remaining (shaded) portion of the disc equals M (2 kg). The moment of inertia of such a disc relative to the axis passing through the geometrical centre of the original disc and perpendicular to the plane of the disc is x kgm2. Then the value of x is

A uniform disc of radius R (3 m) has a round disc of radius R/3 cut fr

1.	A uniform disc of radius R (3 m) has a round disc of radius R/3 cut from it as shown in the figure. The mass of the remaining (shaded) portion of the disc equals M (2 kg). The moment of inertia of such a disc relative to the axis passing through the geometrical centre of the original disc and perpendicular to the plane of the disc is x kgm2. Then the value of x is
Answer» A uniform disc of radius $R$ ( $3 m$ ) has a round disc of radius $R / 3$ cut from it as shown in the figure. The mass of the remaining (shaded) portion of the disc equals $M$ ( $2 k g$ ). The moment of inertia of such a disc relative to the axis passing through the geometrical centre of the original disc and perpendicular to the plane of the disc is $x k g m^{2}$ . Then the value of $x$ is

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