A uniform cable of mass ‘M’ and length ‘L’ is placed on a hori

1.	A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface such that its (1/n)th part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be :(A) nMgL (B) MgL/2n²(C) 2MgL/n²(D) MgL/n²
Answer» hi mate....♥ A UNIFORM cable of mass M and LENGTH L is placed on a horizontal surface such that its 1/n TH parth is HANGING below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be: a) MgL/n² b) MgL/2n² c) 2MgL/n² d) nMgL hope it was helpful ♥

A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface such that its (1/n)th part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be :(A) nMgL (B) MgL/2n²(C) 2MgL/n²(D) MgL/n²

Answer»

hi mate....♥

A UNIFORM cable of mass M and LENGTH L is placed on a horizontal surface such that its

1/n TH parth is HANGING below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be:

a) MgL/n²

b) MgL/2n²

c) 2MgL/n²

d) nMgL

hope it was helpful ♥

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A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface such that its (1/n)th part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be :(A) nMgL (B) MgL/2n²(C) 2MgL/n²(D) MgL/n²

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