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A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the U-shaped tube until the vertical height of the water column is `15.0 cm`. (a) What is the gauge pressure at the water mercury interface ? (b) Calculate the vertical distance h from the top of the mercury in the right hand arm of the tube to the top of the water in the left-hand arm. . |
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Answer» Correct Answer - A::C (a) Gauge pressure=`rho_(w)gh_(w)` `=(10^(3))(9.8)(0.15)` `=1470 N//m^(2)` (b) Let us calculate pressure of two sides at the level of water and mercury interface. `p_(0)+rho_(w)gh_(w)=p_(0)+rho_(Hg)gh_(Hg)` `:. (1) (15) = (13.6) (15-h)` `h =13/9 cm` |
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