1.

A two number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places.Find the number.​

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Let us assume  the two digit number to be ,  x + 10 y

It is ALSO GIVEN that the product of its digits is 6 , \implies x × y = 6\longrightarrow (1)

It is also told that if  9 is added to the number, the digits interchange their places ,  \implies 10x + y + 9 = 10y + x  \longrightarrow (2)

On Solving (2) ,

10x + y  + 9 = 10y + x

( 10x - x ) + ( y - 10 y ) +9 = 0

9x - 9y + 9 = 0

x − y + 1 = 0

y = x + 1  \longrightarrow (3)

Substituting the value of y in (3) in (1)

x ( x + 1 ) = 6

x² + x = 6

Now Let us SOLVE the equation , x² + x = 6

x² + x - 6

Product = -6

Sum = +1

\implies x² + 3x − 2x −6 = 0

\implies (x+3) (x−2) = 0

x = -3

and

x = 2

Therefore x = 2 , substituting x = 2 in x + 10 y we GET ,

∴ The  two digit number = 10×2 + 3 = 23

Let us Verify The Answer :-

23 + 9 = 32 , Here the digit got reversed so our answer is correct



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