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A two-digit number is 7 times the sum of its digits. The number formed by reversing the digits is 18 less than the original number. Find the number. |
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Answer» let the digits be X and y.... so NUMBER is 10X + y so as given in ques. , 10x+y = 7(x+y) 3x - 6y = 0 x-2y =0...... eq1 now reversed number is 10y + x so, 10y+x = 10x+y-18 -9X +9y = -18 x-y = 2....... eq2 eq1 - eq2 y= 2 x = 4 so number is 42 |
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