1.

A two digit number is 4 times its sum of digits and 2 times the product of its digits. Find the number.

Answer»

Let a two digit number be 10x + y, where y is unit place digit and x is tens place digit

10x + y = 4(x + y)

⇒ 10x + y = 4x + 4y

⇒ 6x – 3y = 0

⇒ 2x = y …(i)

and 10x + y = 2xy …(ii)

Substituting y = 2x in (ii), we get

10x + 2x = 2x x 2x

⇒ 4x² – 12x = 0

⇒ 4x(x – 3) = 0

⇒ x = 0, 3

where x = 0, y = 0

when x = 3, y = 2 x 3 = 6

∴ Required number is

10x + y = 10 x 3 + 6 = 36



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