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A two digit number is 4 times its sum of digits and 2 times the product of its digits. Find the number. |
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Answer» Let a two digit number be 10x + y, where y is unit place digit and x is tens place digit 10x + y = 4(x + y) ⇒ 10x + y = 4x + 4y ⇒ 6x – 3y = 0 ⇒ 2x = y …(i) and 10x + y = 2xy …(ii) Substituting y = 2x in (ii), we get 10x + 2x = 2x x 2x ⇒ 4x² – 12x = 0 ⇒ 4x(x – 3) = 0 ⇒ x = 0, 3 where x = 0, y = 0 when x = 3, y = 2 x 3 = 6 ∴ Required number is 10x + y = 10 x 3 + 6 = 36 |
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